City H and City J is 370 km apart. Tim left City H for City J at 9.00 a.m. travelling at an average speed of 74 km/h. John left City H later than Tim and caught up with him at 11.00 a.m. John was travelling at a speed of 111 km/h.
- At what time did John leave City H?
- How much later did Tim arrive in City J than John? Express your answer in h as a fraction or mixed number.
(a)
From 9.00 a.m. to 11.00 a.m. = 2 h
Distance that Tim covered when John caught up with Tim
= 2 x 74
= 148 km
Time that John took to travel 148 km
= 148 ÷ 111
= 1
13 h
1 h = 60 min
13 h =
13 x 60 = 20 min
1
13 h = 1 h 20 min
Time that John left City H:
1 h 20 min before 11.00 a.m. = 9.40 a.m.
(b)
Remaining distance that they had to cover to reach City J
= 370 - 148
= 222 km
Duration that John had to travel before reaching City J
= 222 ÷ 111
= 2 h
Duration that Tim had to travel before reaching City J
= 222 ÷ 74
= 3 h
Duration that Tim took to arrive later than John in City J
= 3 - 2
= 1 h
Answer(s): (a) 9.40 a.m.; (b) 1 h