City B and City C is 360 km apart. Andy left City B for City C at 11.00 a.m. travelling at an average speed of 60 km/h. Japheth left City B later than Andy and caught up with him at 2.00 p.m. Japheth was travelling at a speed of 108 km/h.

1. At what time did Japheth leave City B?
2. How much later did Andy arrive in City C than Japheth? Express your answer in h as a fraction or mixed number.

(a)
From 11.00 a.m. to 2.00 p.m. = 3 h

Distance that Andy covered when Japheth caught up with Andy
= 3 x 60
= 180 km

Time that Japheth took to travel 180 km
= 180 ÷ 108
= 1²₃ h

1 h = 60 min
²₃ h = ²₃ x 60 = 40 min
1²₃ h = 1 h 40 min

Time that Japheth left City B:
1 h 40 min before 2.00 p.m. = 12.20 p.m.

(b)
Remaining distance that they had to cover to reach City C
= 360 - 180
= 180 km

Duration that Japheth had to travel before reaching City C
= 180 ÷ 108
= 1²₃ h

Duration that Andy had to travel before reaching City C
= 180 ÷ 60
= 3 h

Duration that Andy took to arrive later than Japheth in City C
= 3 - 1²₃
= 1¹₃ h

Answer(s): (a) 12.20 p.m.; (b) 1¹₃ h