City P and City Q is 504 km apart. Riordan left City P for City Q at 10.00 a.m. travelling at an average speed of 63 km/h. Neave left City P later than Riordan and caught up with him at 2.00 p.m. Neave was travelling at a speed of 112 km/h.
- At what time did Neave leave City P?
- How much later did Riordan arrive in City Q than Neave? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 2.00 p.m. = 4 h
Distance that Riordan covered when Neave caught up with Riordan
= 4 x 63
= 252 km
Time that Neave took to travel 252 km
= 252 ÷ 112
= 2
14 h
1 h = 60 min
14 h =
14 x 60 = 15 min
2
14 h = 2 h 15 min
Time that Neave left City P:
2 h 15 min before 2.00 p.m. = 11.45 a.m.
(b)
Remaining distance that they had to cover to reach City Q
= 504 - 252
= 252 km
Duration that Neave had to travel before reaching City Q
= 252 ÷ 112
= 2
14 h
Duration that Riordan had to travel before reaching City Q
= 252 ÷ 63
= 4 h
Duration that Riordan took to arrive later than Neave in City Q
= 4 - 2
14= 1
34 h
Answer(s): (a) 11.45 a.m.; (b) 1
34 h