City B and City C is 330 km apart. Brandon left City B for City C at 7.00 a.m. travelling at an average speed of 66 km/h. Fabian left City B later than Brandon and caught up with him at 10.00 a.m. Fabian was travelling at a speed of 88 km/h.

1. At what time did Fabian leave City B?
2. How much later did Brandon arrive in City C than Fabian? Express your answer in h as a fraction or mixed number.

(a)
From 7.00 a.m. to 10.00 a.m. = 3 h

Distance that Brandon covered when Fabian caught up with Brandon
= 3 x 66
= 198 km

Time that Fabian took to travel 198 km
= 198 ÷ 88
= 2¹₄ h

1 h = 60 min
¹₄ h = ¹₄ x 60 = 15 min
2¹₄ h = 2 h 15 min

Time that Fabian left City B:
2 h 15 min before 10.00 a.m. = 7.45 a.m.

(b)
Remaining distance that they had to cover to reach City C
= 330 - 198
= 132 km

Duration that Fabian had to travel before reaching City C
= 132 ÷ 88
= 1¹₂ h

Duration that Brandon had to travel before reaching City C
= 132 ÷ 66
= 2 h

Duration that Brandon took to arrive later than Fabian in City C
= 2 - 1¹₂
= ¹₂ h

Answer(s): (a) 7.45 a.m.; (b) ¹₂ h