City T and City U is 432 km apart. Oscar left City T for City U at 10.00 a.m. travelling at an average speed of 72 km/h. Cole left City T later than Oscar and caught up with him at 1.00 p.m. Cole was travelling at a speed of 96 km/h.
- At what time did Cole leave City T?
- How much later did Oscar arrive in City U than Cole? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 1.00 p.m. = 3 h
Distance that Oscar covered when Cole caught up with Oscar
= 3 x 72
= 216 km
Time that Cole took to travel 216 km
= 216 ÷ 96
= 2
14 h
1 h = 60 min
14 h =
14 x 60 = 15 min
2
14 h = 2 h 15 min
Time that Cole left City T:
2 h 15 min before 1.00 p.m. = 10.45 a.m.
(b)
Remaining distance that they had to cover to reach City U
= 432 - 216
= 216 km
Duration that Cole had to travel before reaching City U
= 216 ÷ 96
= 2
14 h
Duration that Oscar had to travel before reaching City U
= 216 ÷ 72
= 3 h
Duration that Oscar took to arrive later than Cole in City U
= 3 - 2
14=
34 h
Answer(s): (a) 10.45 a.m.; (b)
34 h