City E and City F is 480 km apart. Carl left City E for City F at 10.00 a.m. travelling at an average speed of 60 km/h. Will left City E later than Carl and caught up with him at 1.00 p.m. Will was travelling at a speed of 80 km/h.

1. At what time did Will leave City E?
2. How much later did Carl arrive in City F than Will? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 1.00 p.m. = 3 h

Distance that Carl covered when Will caught up with Carl
= 3 x 60
= 180 km

Time that Will took to travel 180 km
= 180 ÷ 80
= 2¹₄ h

1 h = 60 min
¹₄ h = ¹₄ x 60 = 15 min
2¹₄ h = 2 h 15 min

Time that Will left City E:
2 h 15 min before 1.00 p.m. = 10.45 a.m.

(b)
Remaining distance that they had to cover to reach City F
= 480 - 180
= 300 km

Duration that Will had to travel before reaching City F
= 300 ÷ 80
= 3³₄ h

Duration that Carl had to travel before reaching City F
= 300 ÷ 60
= 5 h

Duration that Carl took to arrive later than Will in City F
= 5 - 3³₄
= 1¹₄ h

Answer(s): (a) 10.45 a.m.; (b) 1¹₄ h