City M and City N is 455 km apart. Lee left City M for City N at 9.00 a.m. travelling at an average speed of 65 km/h. Julian left City M later than Lee and caught up with him at 11.00 a.m. Julian was travelling at a speed of 104 km/h.

1. At what time did Julian leave City M?
2. How much later did Lee arrive in City N than Julian? Express your answer in h as a fraction or mixed number.

(a)
From 9.00 a.m. to 11.00 a.m. = 2 h

Distance that Lee covered when Julian caught up with Lee
= 2 x 65
= 130 km

Time that Julian took to travel 130 km
= 130 ÷ 104
= 1¹₄ h

1 h = 60 min
¹₄ h = ¹₄ x 60 = 15 min
1¹₄ h = 1 h 15 min

Time that Julian left City M:
1 h 15 min before 11.00 a.m. = 9.45 a.m.

(b)
Remaining distance that they had to cover to reach City N
= 455 - 130
= 325 km

Duration that Julian had to travel before reaching City N
= 325 ÷ 104
= 3¹₈ h

Duration that Lee had to travel before reaching City N
= 325 ÷ 65
= 5 h

Duration that Lee took to arrive later than Julian in City N
= 5 - 3¹₈
= 1⁷₈ h

Answer(s): (a) 9.45 a.m.; (b) 1⁷₈ h