City Q and City R is 300 km apart. Flynn left City Q for City R at 8.00 a.m. travelling at an average speed of 60 km/h. Justin left City Q later than Flynn and caught up with him at 10.00 a.m. Justin was travelling at a speed of 96 km/h.

1. At what time did Justin leave City Q?
2. How much later did Flynn arrive in City R than Justin? Express your answer in h as a fraction or mixed number.

(a)
From 8.00 a.m. to 10.00 a.m. = 2 h

Distance that Flynn covered when Justin caught up with Flynn
= 2 x 60
= 120 km

Time that Justin took to travel 120 km
= 120 ÷ 96
= 1¹₄ h

1 h = 60 min
¹₄ h = ¹₄ x 60 = 15 min
1¹₄ h = 1 h 15 min

Time that Justin left City Q:
1 h 15 min before 10.00 a.m. = 8.45 a.m.

(b)
Remaining distance that they had to cover to reach City R
= 300 - 120
= 180 km

Duration that Justin had to travel before reaching City R
= 180 ÷ 96
= 1⁷₈ h

Duration that Flynn had to travel before reaching City R
= 180 ÷ 60
= 3 h

Duration that Flynn took to arrive later than Justin in City R
= 3 - 1⁷₈
= 1¹₈ h

Answer(s): (a) 8.45 a.m.; (b) 1¹₈ h