City G and City H is 272 km apart. Jenson left City G for City H at 11.00 a.m. travelling at an average speed of 68 km/h. Fabian left City G later than Jenson and caught up with him at 1.00 p.m. Fabian was travelling at a speed of 102 km/h.

1. At what time did Fabian leave City G?
2. How much later did Jenson arrive in City H than Fabian? Express your answer in h as a fraction or mixed number.

(a)
From 11.00 a.m. to 1.00 p.m. = 2 h

Distance that Jenson covered when Fabian caught up with Jenson
= 2 x 68
= 136 km

Time that Fabian took to travel 136 km
= 136 ÷ 102
= 1¹₃ h

1 h = 60 min
¹₃ h = ¹₃ x 60 = 20 min
1¹₃ h = 1 h 20 min

Time that Fabian left City G:
1 h 20 min before 1.00 p.m. = 11.40 a.m.

(b)
Remaining distance that they had to cover to reach City H
= 272 - 136
= 136 km

Duration that Fabian had to travel before reaching City H
= 136 ÷ 102
= 1¹₃ h

Duration that Jenson had to travel before reaching City H
= 136 ÷ 68
= 2 h

Duration that Jenson took to arrive later than Fabian in City H
= 2 - 1¹₃
= ²₃ h

Answer(s): (a) 11.40 a.m.; (b) ²₃ h