City V and City W is 360 km apart. Sean left City V for City W at 10.00 a.m. travelling at an average speed of 60 km/h. Carl left City V later than Sean and caught up with him at 1.00 p.m. Carl was travelling at a speed of 80 km/h.
- At what time did Carl leave City V?
- How much later did Sean arrive in City W than Carl? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 1.00 p.m. = 3 h
Distance that Sean covered when Carl caught up with Sean
= 3 x 60
= 180 km
Time that Carl took to travel 180 km
= 180 ÷ 80
= 2
14 h
1 h = 60 min
14 h =
14 x 60 = 15 min
2
14 h = 2 h 15 min
Time that Carl left City V:
2 h 15 min before 1.00 p.m. = 10.45 a.m.
(b)
Remaining distance that they had to cover to reach City W
= 360 - 180
= 180 km
Duration that Carl had to travel before reaching City W
= 180 ÷ 80
= 2
14 h
Duration that Sean had to travel before reaching City W
= 180 ÷ 60
= 3 h
Duration that Sean took to arrive later than Carl in City W
= 3 - 2
14=
34 h
Answer(s): (a) 10.45 a.m.; (b)
34 h