City G and City H is 518 km apart. Lee left City G for City H at 10.00 a.m. travelling at an average speed of 74 km/h. Oliver left City G later than Lee and caught up with him at 12.00 p.m. Oliver was travelling at a speed of 111 km/h.
- At what time did Oliver leave City G?
- How much later did Lee arrive in City H than Oliver? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that Lee covered when Oliver caught up with Lee
= 2 x 74
= 148 km
Time that Oliver took to travel 148 km
= 148 ÷ 111
= 1
13 h
1 h = 60 min
13 h =
13 x 60 = 20 min
1
13 h = 1 h 20 min
Time that Oliver left City G:
1 h 20 min before 12.00 p.m. = 10.40 a.m.
(b)
Remaining distance that they had to cover to reach City H
= 518 - 148
= 370 km
Duration that Oliver had to travel before reaching City H
= 370 ÷ 111
= 3
13 h
Duration that Lee had to travel before reaching City H
= 370 ÷ 74
= 5 h
Duration that Lee took to arrive later than Oliver in City H
= 5 - 3
13= 1
23 h
Answer(s): (a) 10.40 a.m.; (b) 1
23 h