City L and City M is 456 km apart. Jenson left City L for City M at 10.00 a.m. travelling at an average speed of 76 km/h. Howard left City L later than Jenson and caught up with him at 12.00 p.m. Howard was travelling at a speed of 96 km/h.
- At what time did Howard leave City L?
- How much later did Jenson arrive in City M than Howard? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that Jenson covered when Howard caught up with Jenson
= 2 x 76
= 152 km
Time that Howard took to travel 152 km
= 152 ÷ 96
= 1
712 h
1 h = 60 min
712 h =
712 x 60 = 35 min
1
712 h = 1 h 35 min
Time that Howard left City L:
1 h 35 min before 12.00 p.m. = 10.25 a.m.
(b)
Remaining distance that they had to cover to reach City M
= 456 - 152
= 304 km
Duration that Howard had to travel before reaching City M
= 304 ÷ 96
= 3
16 h
Duration that Jenson had to travel before reaching City M
= 304 ÷ 76
= 4 h
Duration that Jenson took to arrive later than Howard in City M
= 4 - 3
16=
56 h
Answer(s): (a) 10.25 a.m.; (b)
56 h