City Z and City A is 320 km apart. Fred left City Z for City A at 10.00 a.m. travelling at an average speed of 80 km/h. Neave left City Z later than Fred and caught up with him at 12.00 p.m. Neave was travelling at a speed of 96 km/h.
- At what time did Neave leave City Z?
- How much later did Fred arrive in City A than Neave? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that Fred covered when Neave caught up with Fred
= 2 x 80
= 160 km
Time that Neave took to travel 160 km
= 160 ÷ 96
= 1
23 h
1 h = 60 min
23 h =
23 x 60 = 40 min
1
23 h = 1 h 40 min
Time that Neave left City Z:
1 h 40 min before 12.00 p.m. = 10.20 a.m.
(b)
Remaining distance that they had to cover to reach City A
= 320 - 160
= 160 km
Duration that Neave had to travel before reaching City A
= 160 ÷ 96
= 1
23 h
Duration that Fred had to travel before reaching City A
= 160 ÷ 80
= 2 h
Duration that Fred took to arrive later than Neave in City A
= 2 - 1
23=
13 h
Answer(s): (a) 10.20 a.m.; (b)
13 h