City Q and City R is 434 km apart. Tim left City Q for City R at 9.00 a.m. travelling at an average speed of 62 km/h. Japheth left City Q later than Tim and caught up with him at 12.00 p.m. Japheth was travelling at a speed of 72 km/h.
- At what time did Japheth leave City Q?
- How much later did Tim arrive in City R than Japheth? Express your answer in h as a fraction or mixed number.
(a)
From 9.00 a.m. to 12.00 p.m. = 3 h
Distance that Tim covered when Japheth caught up with Tim
= 3 x 62
= 186 km
Time that Japheth took to travel 186 km
= 186 ÷ 72
= 2
712 h
1 h = 60 min
712 h =
712 x 60 = 35 min
2
712 h = 2 h 35 min
Time that Japheth left City Q:
2 h 35 min before 12.00 p.m. = 9.25 a.m.
(b)
Remaining distance that they had to cover to reach City R
= 434 - 186
= 248 km
Duration that Japheth had to travel before reaching City R
= 248 ÷ 72
= 3
49 h
Duration that Tim had to travel before reaching City R
= 248 ÷ 62
= 4 h
Duration that Tim took to arrive later than Japheth in City R
= 4 - 3
49=
59 h
Answer(s): (a) 9.25 a.m.; (b)
59 h