City J and City K is 504 km apart. Howard left City J for City K at 10.00 a.m. travelling at an average speed of 63 km/h. Vaidev left City J later than Howard and caught up with him at 1.00 p.m. Vaidev was travelling at a speed of 81 km/h.
- At what time did Vaidev leave City J?
- How much later did Howard arrive in City K than Vaidev? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 1.00 p.m. = 3 h
Distance that Howard covered when Vaidev caught up with Howard
= 3 x 63
= 189 km
Time that Vaidev took to travel 189 km
= 189 ÷ 81
= 2
13 h
1 h = 60 min
13 h =
13 x 60 = 20 min
2
13 h = 2 h 20 min
Time that Vaidev left City J:
2 h 20 min before 1.00 p.m. = 10.40 a.m.
(b)
Remaining distance that they had to cover to reach City K
= 504 - 189
= 315 km
Duration that Vaidev had to travel before reaching City K
= 315 ÷ 81
= 3
89 h
Duration that Howard had to travel before reaching City K
= 315 ÷ 63
= 5 h
Duration that Howard took to arrive later than Vaidev in City K
= 5 - 3
89= 1
19 h
Answer(s): (a) 10.40 a.m.; (b) 1
19 h
