City G and City H is 441 km apart. Cole left City G for City H at 11.00 a.m. travelling at an average speed of 63 km/h. Will left City G later than Cole and caught up with him at 2.00 p.m. Will was travelling at a speed of 84 km/h.

1. At what time did Will leave City G?
2. How much later did Cole arrive in City H than Will? Express your answer in h as a fraction or mixed number.

(a)
From 11.00 a.m. to 2.00 p.m. = 3 h

Distance that Cole covered when Will caught up with Cole
= 3 x 63
= 189 km

Time that Will took to travel 189 km
= 189 ÷ 84
= 2¹₄ h

1 h = 60 min
¹₄ h = ¹₄ x 60 = 15 min
2¹₄ h = 2 h 15 min

Time that Will left City G:
2 h 15 min before 2.00 p.m. = 11.45 a.m.

(b)
Remaining distance that they had to cover to reach City H
= 441 - 189
= 252 km

Duration that Will had to travel before reaching City H
= 252 ÷ 84
= 3 h

Duration that Cole had to travel before reaching City H
= 252 ÷ 63
= 4 h

Duration that Cole took to arrive later than Will in City H
= 4 - 3
= 1 h

Answer(s): (a) 11.45 a.m.; (b) 1 h