City G and City H is 528 km apart. Glen left City G for City H at 11.00 a.m. travelling at an average speed of 66 km/h. Paul left City G later than Glen and caught up with him at 3.00 p.m. Paul was travelling at a speed of 96 km/h.
- At what time did Paul leave City G?
- How much later did Glen arrive in City H than Paul? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 3.00 p.m. = 4 h
Distance that Glen covered when Paul caught up with Glen
= 4 x 66
= 264 km
Time that Paul took to travel 264 km
= 264 ÷ 96
= 2
34 h
1 h = 60 min
34 h =
34 x 60 = 45 min
2
34 h = 2 h 45 min
Time that Paul left City G:
2 h 45 min before 3.00 p.m. = 12.15 p.m.
(b)
Remaining distance that they had to cover to reach City H
= 528 - 264
= 264 km
Duration that Paul had to travel before reaching City H
= 264 ÷ 96
= 2
34 h
Duration that Glen had to travel before reaching City H
= 264 ÷ 66
= 4 h
Duration that Glen took to arrive later than Paul in City H
= 4 - 2
34= 1
14 h
Answer(s): (a) 12.15 p.m.; (b) 1
14 h
