City F and City G is 300 km apart. Tom left City F for City G at 11.00 a.m. travelling at an average speed of 75 km/h. Zeph left City F later than Tom and caught up with him at 1.00 p.m. Zeph was travelling at a speed of 100 km/h.
- At what time did Zeph leave City F?
- How much later did Tom arrive in City G than Zeph? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 1.00 p.m. = 2 h
Distance that Tom covered when Zeph caught up with Tom
= 2 x 75
= 150 km
Time that Zeph took to travel 150 km
= 150 ÷ 100
= 1
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
1
12 h = 1 h 30 min
Time that Zeph left City F:
1 h 30 min before 1.00 p.m. = 11.30 a.m.
(b)
Remaining distance that they had to cover to reach City G
= 300 - 150
= 150 km
Duration that Zeph had to travel before reaching City G
= 150 ÷ 100
= 1
12 h
Duration that Tom had to travel before reaching City G
= 150 ÷ 75
= 2 h
Duration that Tom took to arrive later than Zeph in City G
= 2 - 1
12=
12 h
Answer(s): (a) 11.30 a.m.; (b)
12 h
