City E and City F is 476 km apart. Paul left City E for City F at 8.00 a.m. travelling at an average speed of 68 km/h. Peter left City E later than Paul and caught up with him at 10.00 a.m. Peter was travelling at a speed of 102 km/h.

1. At what time did Peter leave City E?
2. How much later did Paul arrive in City F than Peter? Express your answer in h as a fraction or mixed number.

(a)
From 8.00 a.m. to 10.00 a.m. = 2 h

Distance that Paul covered when Peter caught up with Paul
= 2 x 68
= 136 km

Time that Peter took to travel 136 km
= 136 ÷ 102
= 1¹₃ h

1 h = 60 min
¹₃ h = ¹₃ x 60 = 20 min
1¹₃ h = 1 h 20 min

Time that Peter left City E:
1 h 20 min before 10.00 a.m. = 8.40 a.m.

(b)
Remaining distance that they had to cover to reach City F
= 476 - 136
= 340 km

Duration that Peter had to travel before reaching City F
= 340 ÷ 102
= 3¹₃ h

Duration that Paul had to travel before reaching City F
= 340 ÷ 68
= 5 h

Duration that Paul took to arrive later than Peter in City F
= 5 - 3¹₃
= 1²₃ h

Answer(s): (a) 8.40 a.m.; (b) 1²₃ h