City E and City F is 567 km apart. Sam left City E for City F at 8.00 a.m. travelling at an average speed of 63 km/h. Flynn left City E later than Sam and caught up with him at 12.00 p.m. Flynn was travelling at a speed of 112 km/h.

1. At what time did Flynn leave City E?
2. How much later did Sam arrive in City F than Flynn? Express your answer in h as a fraction or mixed number.

(a)
From 8.00 a.m. to 12.00 p.m. = 4 h

Distance that Sam covered when Flynn caught up with Sam
= 4 x 63
= 252 km

Time that Flynn took to travel 252 km
= 252 ÷ 112
= 2¹₄ h

1 h = 60 min
¹₄ h = ¹₄ x 60 = 15 min
2¹₄ h = 2 h 15 min

Time that Flynn left City E:
2 h 15 min before 12.00 p.m. = 9.45 a.m.

(b)
Remaining distance that they had to cover to reach City F
= 567 - 252
= 315 km

Duration that Flynn had to travel before reaching City F
= 315 ÷ 112
= 2¹³₁₆ h

Duration that Sam had to travel before reaching City F
= 315 ÷ 63
= 5 h

Duration that Sam took to arrive later than Flynn in City F
= 5 - 2¹³₁₆
= 2³₁₆ h

Answer(s): (a) 9.45 a.m.; (b) 2³₁₆ h