City G and City H is 544 km apart. Seth left City G for City H at 8.00 a.m. travelling at an average speed of 68 km/h. Perry left City G later than Seth and caught up with him at 11.00 a.m. Perry was travelling at a speed of 72 km/h.

1. At what time did Perry leave City G?
2. How much later did Seth arrive in City H than Perry? Express your answer in h as a fraction or mixed number.

(a)
From 8.00 a.m. to 11.00 a.m. = 3 h

Distance that Seth covered when Perry caught up with Seth
= 3 x 68
= 204 km

Time that Perry took to travel 204 km
= 204 ÷ 72
= 2⁵₆ h

1 h = 60 min
⁵₆ h = ⁵₆ x 60 = 50 min
2⁵₆ h = 2 h 50 min

Time that Perry left City G:
2 h 50 min before 11.00 a.m. = 8.10 a.m.

(b)
Remaining distance that they had to cover to reach City H
= 544 - 204
= 340 km

Duration that Perry had to travel before reaching City H
= 340 ÷ 72
= 4¹³₁₈ h

Duration that Seth had to travel before reaching City H
= 340 ÷ 68
= 5 h

Duration that Seth took to arrive later than Perry in City H
= 5 - 4¹³₁₈
= ⁵₁₈ h

Answer(s): (a) 8.10 a.m.; (b) ⁵₁₈ h