City Q and City R is 360 km apart. Valen left City Q for City R at 10.00 a.m. travelling at an average speed of 72 km/h. Sam left City Q later than Valen and caught up with him at 12.00 p.m. Sam was travelling at a speed of 96 km/h.
- At what time did Sam leave City Q?
- How much later did Valen arrive in City R than Sam? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that Valen covered when Sam caught up with Valen
= 2 x 72
= 144 km
Time that Sam took to travel 144 km
= 144 ÷ 96
= 1
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
1
12 h = 1 h 30 min
Time that Sam left City Q:
1 h 30 min before 12.00 p.m. = 10.30 a.m.
(b)
Remaining distance that they had to cover to reach City R
= 360 - 144
= 216 km
Duration that Sam had to travel before reaching City R
= 216 ÷ 96
= 2
14 h
Duration that Valen had to travel before reaching City R
= 216 ÷ 72
= 3 h
Duration that Valen took to arrive later than Sam in City R
= 3 - 2
14=
34 h
Answer(s): (a) 10.30 a.m.; (b)
34 h