City V and City W is 360 km apart. Charlie left City V for City W at 7.00 a.m. travelling at an average speed of 60 km/h. Asher left City V later than Charlie and caught up with him at 10.00 a.m. Asher was travelling at a speed of 72 km/h.
- At what time did Asher leave City V?
- How much later did Charlie arrive in City W than Asher? Express your answer in h as a fraction or mixed number.
(a)
From 7.00 a.m. to 10.00 a.m. = 3 h
Distance that Charlie covered when Asher caught up with Charlie
= 3 x 60
= 180 km
Time that Asher took to travel 180 km
= 180 ÷ 72
= 2
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
2
12 h = 2 h 30 min
Time that Asher left City V:
2 h 30 min before 10.00 a.m. = 7.30 a.m.
(b)
Remaining distance that they had to cover to reach City W
= 360 - 180
= 180 km
Duration that Asher had to travel before reaching City W
= 180 ÷ 72
= 2
12 h
Duration that Charlie had to travel before reaching City W
= 180 ÷ 60
= 3 h
Duration that Charlie took to arrive later than Asher in City W
= 3 - 2
12=
12 h
Answer(s): (a) 7.30 a.m.; (b)
12 h