City J and City K is 378 km apart. Owen left City J for City K at 10.00 a.m. travelling at an average speed of 63 km/h. Asher left City J later than Owen and caught up with him at 1.00 p.m. Asher was travelling at a speed of 108 km/h.

1. At what time did Asher leave City J?
2. How much later did Owen arrive in City K than Asher? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 1.00 p.m. = 3 h

Distance that Owen covered when Asher caught up with Owen
= 3 x 63
= 189 km

Time that Asher took to travel 189 km
= 189 ÷ 108
= 1³₄ h

1 h = 60 min
³₄ h = ³₄ x 60 = 45 min
1³₄ h = 1 h 45 min

Time that Asher left City J:
1 h 45 min before 1.00 p.m. = 11.15 a.m.

(b)
Remaining distance that they had to cover to reach City K
= 378 - 189
= 189 km

Duration that Asher had to travel before reaching City K
= 189 ÷ 108
= 1³₄ h

Duration that Owen had to travel before reaching City K
= 189 ÷ 63
= 3 h

Duration that Owen took to arrive later than Asher in City K
= 3 - 1³₄
= 1¹₄ h

Answer(s): (a) 11.15 a.m.; (b) 1¹₄ h