City U and City V is 560 km apart. Cole left City U for City V at 10.00 a.m. travelling at an average speed of 80 km/h. Vaidev left City U later than Cole and caught up with him at 12.00 p.m. Vaidev was travelling at a speed of 96 km/h.

1. At what time did Vaidev leave City U?
2. How much later did Cole arrive in City V than Vaidev? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 12.00 p.m. = 2 h

Distance that Cole covered when Vaidev caught up with Cole
= 2 x 80
= 160 km

Time that Vaidev took to travel 160 km
= 160 ÷ 96
= 1²₃ h

1 h = 60 min
²₃ h = ²₃ x 60 = 40 min
1²₃ h = 1 h 40 min

Time that Vaidev left City U:
1 h 40 min before 12.00 p.m. = 10.20 a.m.

(b)
Remaining distance that they had to cover to reach City V
= 560 - 160
= 400 km

Duration that Vaidev had to travel before reaching City V
= 400 ÷ 96
= 4¹₆ h

Duration that Cole had to travel before reaching City V
= 400 ÷ 80
= 5 h

Duration that Cole took to arrive later than Vaidev in City V
= 5 - 4¹₆
= ⁵₆ h

Answer(s): (a) 10.20 a.m.; (b) ⁵₆ h