City W and City X is 408 km apart. Perry left City W for City X at 11.00 a.m. travelling at an average speed of 68 km/h. Jeremy left City W later than Perry and caught up with him at 3.00 p.m. Jeremy was travelling at a speed of 96 km/h.
- At what time did Jeremy leave City W?
- How much later did Perry arrive in City X than Jeremy? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 3.00 p.m. = 4 h
Distance that Perry covered when Jeremy caught up with Perry
= 4 x 68
= 272 km
Time that Jeremy took to travel 272 km
= 272 ÷ 96
= 2
56 h
1 h = 60 min
56 h =
56 x 60 = 50 min
2
56 h = 2 h 50 min
Time that Jeremy left City W:
2 h 50 min before 3.00 p.m. = 12.10 p.m.
(b)
Remaining distance that they had to cover to reach City X
= 408 - 272
= 136 km
Duration that Jeremy had to travel before reaching City X
= 136 ÷ 96
= 1
512 h
Duration that Perry had to travel before reaching City X
= 136 ÷ 68
= 2 h
Duration that Perry took to arrive later than Jeremy in City X
= 2 - 1
512=
712 h
Answer(s): (a) 12.10 p.m.; (b)
712 h