City D and City E is 476 km apart. Eric left City D for City E at 7.00 a.m. travelling at an average speed of 68 km/h. Asher left City D later than Eric and caught up with him at 11.00 a.m. Asher was travelling at a speed of 102 km/h.

1. At what time did Asher leave City D?
2. How much later did Eric arrive in City E than Asher? Express your answer in h as a fraction or mixed number.

(a)
From 7.00 a.m. to 11.00 a.m. = 4 h

Distance that Eric covered when Asher caught up with Eric
= 4 x 68
= 272 km

Time that Asher took to travel 272 km
= 272 ÷ 102
= 2²₃ h

1 h = 60 min
²₃ h = ²₃ x 60 = 40 min
2²₃ h = 2 h 40 min

Time that Asher left City D:
2 h 40 min before 11.00 a.m. = 8.20 a.m.

(b)
Remaining distance that they had to cover to reach City E
= 476 - 272
= 204 km

Duration that Asher had to travel before reaching City E
= 204 ÷ 102
= 2 h

Duration that Eric had to travel before reaching City E
= 204 ÷ 68
= 3 h

Duration that Eric took to arrive later than Asher in City E
= 3 - 2
= 1 h

Answer(s): (a) 8.20 a.m.; (b) 1 h