City G and City H is 532 km apart. Bryan left City G for City H at 8.00 a.m. travelling at an average speed of 76 km/h. Julian left City G later than Bryan and caught up with him at 10.00 a.m. Julian was travelling at a speed of 114 km/h.

1. At what time did Julian leave City G?
2. How much later did Bryan arrive in City H than Julian? Express your answer in h as a fraction or mixed number.

(a)
From 8.00 a.m. to 10.00 a.m. = 2 h

Distance that Bryan covered when Julian caught up with Bryan
= 2 x 76
= 152 km

Time that Julian took to travel 152 km
= 152 ÷ 114
= 1¹₃ h

1 h = 60 min
¹₃ h = ¹₃ x 60 = 20 min
1¹₃ h = 1 h 20 min

Time that Julian left City G:
1 h 20 min before 10.00 a.m. = 8.40 a.m.

(b)
Remaining distance that they had to cover to reach City H
= 532 - 152
= 380 km

Duration that Julian had to travel before reaching City H
= 380 ÷ 114
= 3¹₃ h

Duration that Bryan had to travel before reaching City H
= 380 ÷ 76
= 5 h

Duration that Bryan took to arrive later than Julian in City H
= 5 - 3¹₃
= 1²₃ h

Answer(s): (a) 8.40 a.m.; (b) 1²₃ h