City H and City J is 396 km apart. Zeph left City H for City J at 10.00 a.m. travelling at an average speed of 66 km/h. Will left City H later than Zeph and caught up with him at 2.00 p.m. Will was travelling at a speed of 96 km/h.

1. At what time did Will leave City H?
2. How much later did Zeph arrive in City J than Will? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 2.00 p.m. = 4 h

Distance that Zeph covered when Will caught up with Zeph
= 4 x 66
= 264 km

Time that Will took to travel 264 km
= 264 ÷ 96
= 2³₄ h

1 h = 60 min
³₄ h = ³₄ x 60 = 45 min
2³₄ h = 2 h 45 min

Time that Will left City H:
2 h 45 min before 2.00 p.m. = 11.15 a.m.

(b)
Remaining distance that they had to cover to reach City J
= 396 - 264
= 132 km

Duration that Will had to travel before reaching City J
= 132 ÷ 96
= 1³₈ h

Duration that Zeph had to travel before reaching City J
= 132 ÷ 66
= 2 h

Duration that Zeph took to arrive later than Will in City J
= 2 - 1³₈
= ⁵₈ h

Answer(s): (a) 11.15 a.m.; (b) ⁵₈ h