City H and City J is 552 km apart. Tim left City H for City J at 10.00 a.m. travelling at an average speed of 69 km/h. John left City H later than Tim and caught up with him at 1.00 p.m. John was travelling at a speed of 92 km/h.
- At what time did John leave City H?
- How much later did Tim arrive in City J than John? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 1.00 p.m. = 3 h
Distance that Tim covered when John caught up with Tim
= 3 x 69
= 207 km
Time that John took to travel 207 km
= 207 ÷ 92
= 2
14 h
1 h = 60 min
14 h =
14 x 60 = 15 min
2
14 h = 2 h 15 min
Time that John left City H:
2 h 15 min before 1.00 p.m. = 10.45 a.m.
(b)
Remaining distance that they had to cover to reach City J
= 552 - 207
= 345 km
Duration that John had to travel before reaching City J
= 345 ÷ 92
= 3
34 h
Duration that Tim had to travel before reaching City J
= 345 ÷ 69
= 5 h
Duration that Tim took to arrive later than John in City J
= 5 - 3
34= 1
14 h
Answer(s): (a) 10.45 a.m.; (b) 1
14 h
