City A and City B is 264 km apart. Japheth left City A for City B at 11.00 a.m. travelling at an average speed of 66 km/h. Andy left City A later than Japheth and caught up with him at 1.00 p.m. Andy was travelling at a speed of 88 km/h.

1. At what time did Andy leave City A?
2. How much later did Japheth arrive in City B than Andy? Express your answer in h as a fraction or mixed number.

(a)
From 11.00 a.m. to 1.00 p.m. = 2 h

Distance that Japheth covered when Andy caught up with Japheth
= 2 x 66
= 132 km

Time that Andy took to travel 132 km
= 132 ÷ 88
= 1¹₂ h

1 h = 60 min
¹₂ h = ¹₂ x 60 = 30 min
1¹₂ h = 1 h 30 min

Time that Andy left City A:
1 h 30 min before 1.00 p.m. = 11.30 a.m.

(b)
Remaining distance that they had to cover to reach City B
= 264 - 132
= 132 km

Duration that Andy had to travel before reaching City B
= 132 ÷ 88
= 1¹₂ h

Duration that Japheth had to travel before reaching City B
= 132 ÷ 66
= 2 h

Duration that Japheth took to arrive later than Andy in City B
= 2 - 1¹₂
= ¹₂ h

Answer(s): (a) 11.30 a.m.; (b) ¹₂ h