City P and City Q is 576 km apart. Bryan left City P for City Q at 11.00 a.m. travelling at an average speed of 64 km/h. Tom left City P later than Bryan and caught up with him at 3.00 p.m. Tom was travelling at a speed of 96 km/h.
- At what time did Tom leave City P?
- How much later did Bryan arrive in City Q than Tom? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 3.00 p.m. = 4 h
Distance that Bryan covered when Tom caught up with Bryan
= 4 x 64
= 256 km
Time that Tom took to travel 256 km
= 256 ÷ 96
= 2
23 h
1 h = 60 min
23 h =
23 x 60 = 40 min
2
23 h = 2 h 40 min
Time that Tom left City P:
2 h 40 min before 3.00 p.m. = 12.20 p.m.
(b)
Remaining distance that they had to cover to reach City Q
= 576 - 256
= 320 km
Duration that Tom had to travel before reaching City Q
= 320 ÷ 96
= 3
13 h
Duration that Bryan had to travel before reaching City Q
= 320 ÷ 64
= 5 h
Duration that Bryan took to arrive later than Tom in City Q
= 5 - 3
13= 1
23 h
Answer(s): (a) 12.20 p.m.; (b) 1
23 h