City E and City F is 276 km apart. Sean left City E for City F at 7.00 a.m. travelling at an average speed of 69 km/h. Tom left City E later than Sean and caught up with him at 9.00 a.m. Tom was travelling at a speed of 92 km/h.
- At what time did Tom leave City E?
- How much later did Sean arrive in City F than Tom? Express your answer in h as a fraction or mixed number.
(a)
From 7.00 a.m. to 9.00 a.m. = 2 h
Distance that Sean covered when Tom caught up with Sean
= 2 x 69
= 138 km
Time that Tom took to travel 138 km
= 138 ÷ 92
= 1
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
1
12 h = 1 h 30 min
Time that Tom left City E:
1 h 30 min before 9.00 a.m. = 7.30 a.m.
(b)
Remaining distance that they had to cover to reach City F
= 276 - 138
= 138 km
Duration that Tom had to travel before reaching City F
= 138 ÷ 92
= 1
12 h
Duration that Sean had to travel before reaching City F
= 138 ÷ 69
= 2 h
Duration that Sean took to arrive later than Tom in City F
= 2 - 1
12=
12 h
Answer(s): (a) 7.30 a.m.; (b)
12 h
