City M and City N is 330 km apart. Fred left City M for City N at 8.00 a.m. travelling at an average speed of 66 km/h. Paul left City M later than Fred and caught up with him at 11.00 a.m. Paul was travelling at a speed of 72 km/h.

1. At what time did Paul leave City M?
2. How much later did Fred arrive in City N than Paul? Express your answer in h as a fraction or mixed number.

(a)
From 8.00 a.m. to 11.00 a.m. = 3 h

Distance that Fred covered when Paul caught up with Fred
= 3 x 66
= 198 km

Time that Paul took to travel 198 km
= 198 ÷ 72
= 2³₄ h

1 h = 60 min
³₄ h = ³₄ x 60 = 45 min
2³₄ h = 2 h 45 min

Time that Paul left City M:
2 h 45 min before 11.00 a.m. = 8.15 a.m.

(b)
Remaining distance that they had to cover to reach City N
= 330 - 198
= 132 km

Duration that Paul had to travel before reaching City N
= 132 ÷ 72
= 1⁵₆ h

Duration that Fred had to travel before reaching City N
= 132 ÷ 66
= 2 h

Duration that Fred took to arrive later than Paul in City N
= 2 - 1⁵₆
= ¹₆ h

Answer(s): (a) 8.15 a.m.; (b) ¹₆ h