City U and City V is 504 km apart. Glen left City U for City V at 11.00 a.m. travelling at an average speed of 63 km/h. Zane left City U later than Glen and caught up with him at 2.00 p.m. Zane was travelling at a speed of 108 km/h.
- At what time did Zane leave City U?
- How much later did Glen arrive in City V than Zane? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 2.00 p.m. = 3 h
Distance that Glen covered when Zane caught up with Glen
= 3 x 63
= 189 km
Time that Zane took to travel 189 km
= 189 ÷ 108
= 1
34 h
1 h = 60 min
34 h =
34 x 60 = 45 min
1
34 h = 1 h 45 min
Time that Zane left City U:
1 h 45 min before 2.00 p.m. = 12.15 p.m.
(b)
Remaining distance that they had to cover to reach City V
= 504 - 189
= 315 km
Duration that Zane had to travel before reaching City V
= 315 ÷ 108
= 2
1112 h
Duration that Glen had to travel before reaching City V
= 315 ÷ 63
= 5 h
Duration that Glen took to arrive later than Zane in City V
= 5 - 2
1112= 2
112 h
Answer(s): (a) 12.15 p.m.; (b) 2
112 h
