City H and City J is 468 km apart. Asher left City H for City J at 9.00 a.m. travelling at an average speed of 78 km/h. Simon left City H later than Asher and caught up with him at 12.00 p.m. Simon was travelling at a speed of 108 km/h.
- At what time did Simon leave City H?
- How much later did Asher arrive in City J than Simon? Express your answer in h as a fraction or mixed number.
(a)
From 9.00 a.m. to 12.00 p.m. = 3 h
Distance that Asher covered when Simon caught up with Asher
= 3 x 78
= 234 km
Time that Simon took to travel 234 km
= 234 ÷ 108
= 2
16 h
1 h = 60 min
16 h =
16 x 60 = 10 min
2
16 h = 2 h 10 min
Time that Simon left City H:
2 h 10 min before 12.00 p.m. = 9.50 a.m.
(b)
Remaining distance that they had to cover to reach City J
= 468 - 234
= 234 km
Duration that Simon had to travel before reaching City J
= 234 ÷ 108
= 2
16 h
Duration that Asher had to travel before reaching City J
= 234 ÷ 78
= 3 h
Duration that Asher took to arrive later than Simon in City J
= 3 - 2
16=
56 h
Answer(s): (a) 9.50 a.m.; (b)
56 h
