City Q and City R is 310 km apart. Ken left City Q for City R at 10.00 a.m. travelling at an average speed of 62 km/h. Andy left City Q later than Ken and caught up with him at 12.00 p.m. Andy was travelling at a speed of 93 km/h.
- At what time did Andy leave City Q?
- How much later did Ken arrive in City R than Andy? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that Ken covered when Andy caught up with Ken
= 2 x 62
= 124 km
Time that Andy took to travel 124 km
= 124 ÷ 93
= 1
13 h
1 h = 60 min
13 h =
13 x 60 = 20 min
1
13 h = 1 h 20 min
Time that Andy left City Q:
1 h 20 min before 12.00 p.m. = 10.40 a.m.
(b)
Remaining distance that they had to cover to reach City R
= 310 - 124
= 186 km
Duration that Andy had to travel before reaching City R
= 186 ÷ 93
= 2 h
Duration that Ken had to travel before reaching City R
= 186 ÷ 62
= 3 h
Duration that Ken took to arrive later than Andy in City R
= 3 - 2
= 1 h
Answer(s): (a) 10.40 a.m.; (b) 1 h