City T and City U is 390 km apart. Ivan left City T for City U at 8.00 a.m. travelling at an average speed of 78 km/h. Howard left City T later than Ivan and caught up with him at 11.00 a.m. Howard was travelling at a speed of 104 km/h.
- At what time did Howard leave City T?
- How much later did Ivan arrive in City U than Howard? Express your answer in h as a fraction or mixed number.
(a)
From 8.00 a.m. to 11.00 a.m. = 3 h
Distance that Ivan covered when Howard caught up with Ivan
= 3 x 78
= 234 km
Time that Howard took to travel 234 km
= 234 ÷ 104
= 2
14 h
1 h = 60 min
14 h =
14 x 60 = 15 min
2
14 h = 2 h 15 min
Time that Howard left City T:
2 h 15 min before 11.00 a.m. = 8.45 a.m.
(b)
Remaining distance that they had to cover to reach City U
= 390 - 234
= 156 km
Duration that Howard had to travel before reaching City U
= 156 ÷ 104
= 1
12 h
Duration that Ivan had to travel before reaching City U
= 156 ÷ 78
= 2 h
Duration that Ivan took to arrive later than Howard in City U
= 2 - 1
12=
12 h
Answer(s): (a) 8.45 a.m.; (b)
12 h