City K and City L is 264 km apart. Sean left City K for City L at 10.00 a.m. travelling at an average speed of 66 km/h. Wesley left City K later than Sean and caught up with him at 12.00 p.m. Wesley was travelling at a speed of 99 km/h.

1. At what time did Wesley leave City K?
2. How much later did Sean arrive in City L than Wesley? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 12.00 p.m. = 2 h

Distance that Sean covered when Wesley caught up with Sean
= 2 x 66
= 132 km

Time that Wesley took to travel 132 km
= 132 ÷ 99
= 1¹₃ h

1 h = 60 min
¹₃ h = ¹₃ x 60 = 20 min
1¹₃ h = 1 h 20 min

Time that Wesley left City K:
1 h 20 min before 12.00 p.m. = 10.40 a.m.

(b)
Remaining distance that they had to cover to reach City L
= 264 - 132
= 132 km

Duration that Wesley had to travel before reaching City L
= 132 ÷ 99
= 1¹₃ h

Duration that Sean had to travel before reaching City L
= 132 ÷ 66
= 2 h

Duration that Sean took to arrive later than Wesley in City L
= 2 - 1¹₃
= ²₃ h

Answer(s): (a) 10.40 a.m.; (b) ²₃ h