City G and City H is 264 km apart. Warren left City G for City H at 10.00 a.m. travelling at an average speed of 66 km/h. Tom left City G later than Warren and caught up with him at 12.00 p.m. Tom was travelling at a speed of 88 km/h.
- At what time did Tom leave City G?
- How much later did Warren arrive in City H than Tom? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that Warren covered when Tom caught up with Warren
= 2 x 66
= 132 km
Time that Tom took to travel 132 km
= 132 ÷ 88
= 1
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
1
12 h = 1 h 30 min
Time that Tom left City G:
1 h 30 min before 12.00 p.m. = 10.30 a.m.
(b)
Remaining distance that they had to cover to reach City H
= 264 - 132
= 132 km
Duration that Tom had to travel before reaching City H
= 132 ÷ 88
= 1
12 h
Duration that Warren had to travel before reaching City H
= 132 ÷ 66
= 2 h
Duration that Warren took to arrive later than Tom in City H
= 2 - 1
12=
12 h
Answer(s): (a) 10.30 a.m.; (b)
12 h
