City U and City V is 462 km apart. Seth left City U for City V at 7.00 a.m. travelling at an average speed of 77 km/h. Jeremy left City U later than Seth and caught up with him at 10.00 a.m. Jeremy was travelling at a speed of 84 km/h.

1. At what time did Jeremy leave City U?
2. How much later did Seth arrive in City V than Jeremy? Express your answer in h as a fraction or mixed number.

(a)
From 7.00 a.m. to 10.00 a.m. = 3 h

Distance that Seth covered when Jeremy caught up with Seth
= 3 x 77
= 231 km

Time that Jeremy took to travel 231 km
= 231 ÷ 84
= 2³₄ h

1 h = 60 min
³₄ h = ³₄ x 60 = 45 min
2³₄ h = 2 h 45 min

Time that Jeremy left City U:
2 h 45 min before 10.00 a.m. = 7.15 a.m.

(b)
Remaining distance that they had to cover to reach City V
= 462 - 231
= 231 km

Duration that Jeremy had to travel before reaching City V
= 231 ÷ 84
= 2³₄ h

Duration that Seth had to travel before reaching City V
= 231 ÷ 77
= 3 h

Duration that Seth took to arrive later than Jeremy in City V
= 3 - 2³₄
= ¹₄ h

Answer(s): (a) 7.15 a.m.; (b) ¹₄ h