City V and City W is 350 km apart. Jenson left City V for City W at 10.00 a.m. travelling at an average speed of 70 km/h. Tommy left City V later than Jenson and caught up with him at 1.00 p.m. Tommy was travelling at a speed of 84 km/h.

1. At what time did Tommy leave City V?
2. How much later did Jenson arrive in City W than Tommy? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 1.00 p.m. = 3 h

Distance that Jenson covered when Tommy caught up with Jenson
= 3 x 70
= 210 km

Time that Tommy took to travel 210 km
= 210 ÷ 84
= 2¹₂ h

1 h = 60 min
¹₂ h = ¹₂ x 60 = 30 min
2¹₂ h = 2 h 30 min

Time that Tommy left City V:
2 h 30 min before 1.00 p.m. = 10.30 a.m.

(b)
Remaining distance that they had to cover to reach City W
= 350 - 210
= 140 km

Duration that Tommy had to travel before reaching City W
= 140 ÷ 84
= 1²₃ h

Duration that Jenson had to travel before reaching City W
= 140 ÷ 70
= 2 h

Duration that Jenson took to arrive later than Tommy in City W
= 2 - 1²₃
= ¹₃ h

Answer(s): (a) 10.30 a.m.; (b) ¹₃ h