City U and City V is 256 km apart. Zane left City U for City V at 10.00 a.m. travelling at an average speed of 64 km/h. Jack left City U later than Zane and caught up with him at 12.00 p.m. Jack was travelling at a speed of 96 km/h.
- At what time did Jack leave City U?
- How much later did Zane arrive in City V than Jack? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that Zane covered when Jack caught up with Zane
= 2 x 64
= 128 km
Time that Jack took to travel 128 km
= 128 ÷ 96
= 1
13 h
1 h = 60 min
13 h =
13 x 60 = 20 min
1
13 h = 1 h 20 min
Time that Jack left City U:
1 h 20 min before 12.00 p.m. = 10.40 a.m.
(b)
Remaining distance that they had to cover to reach City V
= 256 - 128
= 128 km
Duration that Jack had to travel before reaching City V
= 128 ÷ 96
= 1
13 h
Duration that Zane had to travel before reaching City V
= 128 ÷ 64
= 2 h
Duration that Zane took to arrive later than Jack in City V
= 2 - 1
13=
23 h
Answer(s): (a) 10.40 a.m.; (b)
23 h
