City C and City D is 462 km apart. Tom left City C for City D at 8.00 a.m. travelling at an average speed of 66 km/h. George left City C later than Tom and caught up with him at 11.00 a.m. George was travelling at a speed of 88 km/h.

1. At what time did George leave City C?
2. How much later did Tom arrive in City D than George? Express your answer in h as a fraction or mixed number.

(a)
From 8.00 a.m. to 11.00 a.m. = 3 h

Distance that Tom covered when George caught up with Tom
= 3 x 66
= 198 km

Time that George took to travel 198 km
= 198 ÷ 88
= 2¹₄ h

1 h = 60 min
¹₄ h = ¹₄ x 60 = 15 min
2¹₄ h = 2 h 15 min

Time that George left City C:
2 h 15 min before 11.00 a.m. = 8.45 a.m.

(b)
Remaining distance that they had to cover to reach City D
= 462 - 198
= 264 km

Duration that George had to travel before reaching City D
= 264 ÷ 88
= 3 h

Duration that Tom had to travel before reaching City D
= 264 ÷ 66
= 4 h

Duration that Tom took to arrive later than George in City D
= 4 - 3
= 1 h

Answer(s): (a) 8.45 a.m.; (b) 1 h