City H and City J is 576 km apart. Pierre left City H for City J at 9.00 a.m. travelling at an average speed of 72 km/h. Seth left City H later than Pierre and caught up with him at 12.00 p.m. Seth was travelling at a speed of 96 km/h.
- At what time did Seth leave City H?
- How much later did Pierre arrive in City J than Seth? Express your answer in h as a fraction or mixed number.
(a)
From 9.00 a.m. to 12.00 p.m. = 3 h
Distance that Pierre covered when Seth caught up with Pierre
= 3 x 72
= 216 km
Time that Seth took to travel 216 km
= 216 ÷ 96
= 2
14 h
1 h = 60 min
14 h =
14 x 60 = 15 min
2
14 h = 2 h 15 min
Time that Seth left City H:
2 h 15 min before 12.00 p.m. = 9.45 a.m.
(b)
Remaining distance that they had to cover to reach City J
= 576 - 216
= 360 km
Duration that Seth had to travel before reaching City J
= 360 ÷ 96
= 3
34 h
Duration that Pierre had to travel before reaching City J
= 360 ÷ 72
= 5 h
Duration that Pierre took to arrive later than Seth in City J
= 5 - 3
34= 1
14 h
Answer(s): (a) 9.45 a.m.; (b) 1
14 h