City V and City W is 396 km apart. Zane left City V for City W at 7.00 a.m. travelling at an average speed of 66 km/h. Caden left City V later than Zane and caught up with him at 9.00 a.m. Caden was travelling at a speed of 72 km/h.

1. At what time did Caden leave City V?
2. How much later did Zane arrive in City W than Caden? Express your answer in h as a fraction or mixed number.

(a)
From 7.00 a.m. to 9.00 a.m. = 2 h

Distance that Zane covered when Caden caught up with Zane
= 2 x 66
= 132 km

Time that Caden took to travel 132 km
= 132 ÷ 72
= 1⁵₆ h

1 h = 60 min
⁵₆ h = ⁵₆ x 60 = 50 min
1⁵₆ h = 1 h 50 min

Time that Caden left City V:
1 h 50 min before 9.00 a.m. = 7.10 a.m.

(b)
Remaining distance that they had to cover to reach City W
= 396 - 132
= 264 km

Duration that Caden had to travel before reaching City W
= 264 ÷ 72
= 3²₃ h

Duration that Zane had to travel before reaching City W
= 264 ÷ 66
= 4 h

Duration that Zane took to arrive later than Caden in City W
= 4 - 3²₃
= ¹₃ h

Answer(s): (a) 7.10 a.m.; (b) ¹₃ h