City A and City B is 540 km apart. Henry left City A for City B at 9.00 a.m. travelling at an average speed of 60 km/h. Ryan left City A later than Henry and caught up with him at 1.00 p.m. Ryan was travelling at a speed of 96 km/h.
- At what time did Ryan leave City A?
- How much later did Henry arrive in City B than Ryan? Express your answer in h as a fraction or mixed number.
(a)
From 9.00 a.m. to 1.00 p.m. = 4 h
Distance that Henry covered when Ryan caught up with Henry
= 4 x 60
= 240 km
Time that Ryan took to travel 240 km
= 240 ÷ 96
= 2
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
2
12 h = 2 h 30 min
Time that Ryan left City A:
2 h 30 min before 1.00 p.m. = 10.30 a.m.
(b)
Remaining distance that they had to cover to reach City B
= 540 - 240
= 300 km
Duration that Ryan had to travel before reaching City B
= 300 ÷ 96
= 3
18 h
Duration that Henry had to travel before reaching City B
= 300 ÷ 60
= 5 h
Duration that Henry took to arrive later than Ryan in City B
= 5 - 3
18= 1
78 h
Answer(s): (a) 10.30 a.m.; (b) 1
78 h
