City Q and City R is 240 km apart. Henry left City Q for City R at 11.00 a.m. travelling at an average speed of 60 km/h. Vaidev left City Q later than Henry and caught up with him at 1.00 p.m. Vaidev was travelling at a speed of 80 km/h.
- At what time did Vaidev leave City Q?
- How much later did Henry arrive in City R than Vaidev? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 1.00 p.m. = 2 h
Distance that Henry covered when Vaidev caught up with Henry
= 2 x 60
= 120 km
Time that Vaidev took to travel 120 km
= 120 ÷ 80
= 1
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
1
12 h = 1 h 30 min
Time that Vaidev left City Q:
1 h 30 min before 1.00 p.m. = 11.30 a.m.
(b)
Remaining distance that they had to cover to reach City R
= 240 - 120
= 120 km
Duration that Vaidev had to travel before reaching City R
= 120 ÷ 80
= 1
12 h
Duration that Henry had to travel before reaching City R
= 120 ÷ 60
= 2 h
Duration that Henry took to arrive later than Vaidev in City R
= 2 - 1
12=
12 h
Answer(s): (a) 11.30 a.m.; (b)
12 h
