City H and City J is 408 km apart. Rael left City H for City J at 11.00 a.m. travelling at an average speed of 68 km/h. Neave left City H later than Rael and caught up with him at 3.00 p.m. Neave was travelling at a speed of 102 km/h.

1. At what time did Neave leave City H?
2. How much later did Rael arrive in City J than Neave? Express your answer in h as a fraction or mixed number.

(a)
From 11.00 a.m. to 3.00 p.m. = 4 h

Distance that Rael covered when Neave caught up with Rael
= 4 x 68
= 272 km

Time that Neave took to travel 272 km
= 272 ÷ 102
= 2²₃ h

1 h = 60 min
²₃ h = ²₃ x 60 = 40 min
2²₃ h = 2 h 40 min

Time that Neave left City H:
2 h 40 min before 3.00 p.m. = 12.20 p.m.

(b)
Remaining distance that they had to cover to reach City J
= 408 - 272
= 136 km

Duration that Neave had to travel before reaching City J
= 136 ÷ 102
= 1¹₃ h

Duration that Rael had to travel before reaching City J
= 136 ÷ 68
= 2 h

Duration that Rael took to arrive later than Neave in City J
= 2 - 1¹₃
= ²₃ h

Answer(s): (a) 12.20 p.m.; (b) ²₃ h