City F and City G is 483 km apart. Peter left City F for City G at 11.00 a.m. travelling at an average speed of 69 km/h. Glen left City F later than Peter and caught up with him at 1.00 p.m. Glen was travelling at a speed of 92 km/h.
- At what time did Glen leave City F?
- How much later did Peter arrive in City G than Glen? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 1.00 p.m. = 2 h
Distance that Peter covered when Glen caught up with Peter
= 2 x 69
= 138 km
Time that Glen took to travel 138 km
= 138 ÷ 92
= 1
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
1
12 h = 1 h 30 min
Time that Glen left City F:
1 h 30 min before 1.00 p.m. = 11.30 a.m.
(b)
Remaining distance that they had to cover to reach City G
= 483 - 138
= 345 km
Duration that Glen had to travel before reaching City G
= 345 ÷ 92
= 3
34 h
Duration that Peter had to travel before reaching City G
= 345 ÷ 69
= 5 h
Duration that Peter took to arrive later than Glen in City G
= 5 - 3
34= 1
14 h
Answer(s): (a) 11.30 a.m.; (b) 1
14 h
